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12c^2+6c=81
We move all terms to the left:
12c^2+6c-(81)=0
a = 12; b = 6; c = -81;
Δ = b2-4ac
Δ = 62-4·12·(-81)
Δ = 3924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3924}=\sqrt{36*109}=\sqrt{36}*\sqrt{109}=6\sqrt{109}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{109}}{2*12}=\frac{-6-6\sqrt{109}}{24} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{109}}{2*12}=\frac{-6+6\sqrt{109}}{24} $
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